Created on 2024-06-20Asked by Chloe Moore (Solvelet student)
Use the Weierstrass substitution to evaluate the integral ∫x2+a2dx.
Solution
To evaluate the integral ∫x2+a2dx using the Weierstrass substitution, we make the substitution x=atanθ. 1. **Determine the differential dx:** Differentiating both sides of x=atanθ with respect to θ, we get: dx=asec2θdθ. 2. **Substitute for x and dx:** Substituting x=atanθ and dx=asec2θdθ into the integral, we get: ∫a2tan2θ+a2asec2θdθ. 3. **Simplify the integrand:** ∫a2tan2θ+a2asec2θdθ=∫a2(tan2θ+1)asec2θdθ.=∫a2sec2θasec2θdθ=∫dθ. 4. **Evaluate the integral:** ∫dθ=θ+C. 5. **Convert back to x:** Since x=atanθ, we have tanθ=ax. Therefore, the final result is: ∫x2+a2dx=arctan(ax)+C.Solved on Solvelet with Basic AI Model
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DefinitionThe Weierstrass substitution is a method used for the reduction of integrals involving trigonometry to integrals involving rational functions. It converts the trigonometric expressions into rational ones by using the trigonometric identities. Illustration: Replace t=tan(2x) ⇒ sin(x)dx becomes equal to 1+t22dt.