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Taylor Series Calculator

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Example
Created on 2024-06-20Asked by Mason Martin (Solvelet student)
Find the Taylor series of f(x)=exf(x) = e^x centered at x=0x = 0.

Solution

To find the Taylor series of f(x)=exf(x) = e^x centered at x=0x = 0: 1. **Formula for the Taylor series:** f(x)=n=0f(n)(a)n!(xa)n. f(x) = \sum_{n=0}^{\infty} \frac{f^{(n)}(a)}{n!} (x - a)^n. 2. **Evaluate the derivatives at a=0a = 0:** f(n)(0)=e0=1nN. f^{(n)}(0) = e^0 = 1 \quad \forall n \in \mathbb{N}. 3. **Form the series:** ex=n=01n!xn. e^x = \sum_{n=0}^{\infty} \frac{1}{n!} x^n. 4. **Result:** The Taylor series of exe^x centered at x=0x = 0 is: ex=1+x+x22!+x33!+x44!+. e^x = 1 + x + \frac{x^2}{2!} + \frac{x^3}{3!} + \frac{x^4}{4!} + \cdots. Solved on Solvelet with Basic AI Model
Some of the related questions asked by Camila Perez on Solvelet
1. Find the Maclaurin series representation of the function f(x)=sin(x)f(x)=\sin(x).2. Use the Taylor series for ex e^x to approximate the value of e0.5 e^{0.5} .,
DefinitionA Taylor series is an infinite sum of terms calculated from the values of the derivatives of a function at a single point. It estimates functions in the neighborhood of that point. E.g.: The Taylor series to ex at x=0 is 1+x+2! x2​+3! x3​+⋯.
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