Created on 2024-06-20Asked by Samuel Taylor (Solvelet student)
Solve the system of linear equations: ⎩⎨⎧x+y+z=62x−y+3z=14−x+4y+z=−2
Solution
To solve the system of linear equations: ⎩⎨⎧x+y+z=62x−y+3z=14−x+4y+z=−2 1. **Write the augmented matrix:** ⎝⎛12−11−14131614−2⎠⎞. 2. **Use Gaussian elimination:** - Multiply the first row by 2 and subtract from the second row. - Add the first row to the third row. - Multiply the new second row and subtract from the third row. 3. **Back-substitution:** - Solve for z. - Substitute z to solve for y. - Substitute z and y to solve for x. 4. **Result:** The solution is x=3, y=1, z=2. Solved on Solvelet with Basic AI Model
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DefinitionLinear equations contain two or more linear equations with the same variables. The common intersection of all the equations are the solutions. For example, the system 2x+3y=6 and x−y=2 has the solution x=3 and y=1.