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Systems of Linear Equations Calculator

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Example
Created on 2024-06-20Asked by Samuel Taylor (Solvelet student)
Solve the system of linear equations: {x+y+z=62xy+3z=14x+4y+z=2 \begin{cases} x + y + z = 6 \\ 2x - y + 3z = 14 \\ -x + 4y + z = -2 \end{cases}

Solution

To solve the system of linear equations: {x+y+z=62xy+3z=14x+4y+z=2 \begin{cases} x + y + z = 6 \\ 2x - y + 3z = 14 \\ -x + 4y + z = -2 \end{cases} 1. **Write the augmented matrix:** (1116213141412). \left(\begin{array}{ccc|c} 1 & 1 & 1 & 6 \\ 2 & -1 & 3 & 14 \\ -1 & 4 & 1 & -2 \end{array}\right). 2. **Use Gaussian elimination:** - Multiply the first row by 2 and subtract from the second row. - Add the first row to the third row. - Multiply the new second row and subtract from the third row. 3. **Back-substitution:** - Solve for zz. - Substitute zz to solve for yy. - Substitute zz and yy to solve for xx. 4. **Result:** The solution is x=3x = 3, y=1y = 1, z=2z = 2. Solved on Solvelet with Basic AI Model
Some of the related questions asked by Eleanor Ramirez on Solvelet
1. Solve the system of linear equations: 3x+2y=83x+2y=8, 4xy=34x−y=3.2. Determine if the system of equations has a unique solution: 2x3y=7 2x-3y=7 , 4x6y=14 4x-6y=14 .,
DefinitionLinear equations contain two or more linear equations with the same variables. The common intersection of all the equations are the solutions. For example, the system 2x+3y=6 and x−y=2 has the solution x=3 and y=1.
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