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Created on 2024-06-20Asked by William Wilson (Solvelet student)
Solve the system of equations: {2x+3y=64xy=5 \begin{cases} 2x + 3y = 6 \\ 4x - y = 5 \end{cases}

Solution

To solve the system of equations: {2x+3y=64xy=5 \begin{cases} 2x + 3y = 6 \\ 4x - y = 5 \end{cases} 1. **Multiply the second equation by 3 to align the coefficients of yy:** 12x3y=15. 12x - 3y = 15. 2. **Add the modified second equation to the first equation:** 2x+3y+12x3y=6+1514x=21x=2114=32. 2x + 3y + 12x - 3y = 6 + 15 \\ 14x = 21 \\ x = \frac{21}{14} = \frac{3}{2}. 3. **Substitute xx back into the first equation:** 2(32)+3y=63+3y=63y=3y=1. 2\left(\frac{3}{2}\right) + 3y = 6 \\ 3 + 3y = 6 \\ 3y = 3 \\ y = 1. 4. **Result:** The solution to the system is x=32x = \frac{3}{2}, y=1y = 1. Solved on Solvelet with Basic AI Model
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DefinitionMathematical solution methods and techniques of equations and problems are methods that solve equations in analytical, numerical and graphical categories. For example, solving the quadratic equation ax2+bx+c=0 using the quadratic formula x=2a−b±b2−4ac​​.
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