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Slope of Tangent Lines Calculator

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Example
Created on 2024-06-20Asked by Chloe Walker (Solvelet student)
Find the slope of the tangent line to the curve y=x23x+2y = x^2 - 3x + 2 at the point x=1x = 1.

Solution

To find the slope of the tangent line to the curve y=x23x+2y = x^2 - 3x + 2 at the point x=1x = 1: 1. **Compute the derivative of yy:** dydx=2x3. \frac{dy}{dx} = 2x - 3. 2. **Evaluate the derivative at x=1x = 1:** dydxx=1=2(1)3=1. \frac{dy}{dx}\Bigg|_{x=1} = 2(1) - 3 = -1. 3. **Result:** The slope of the tangent line at x=1x = 1 is 1-1. Solved on Solvelet with Basic AI Model
Some of the related questions asked by Layla Lee on Solvelet
1. Find the equation of the tangent line to the curve y=x2 y = x^2 at the point (1,1) (1, 1) .2. Determine the slope of the tangent line to the curve y=ln(x) y = \ln(x) at the point (e,1) (e, 1) .,
DefinitionThe slope of a curve passing through that point is obtained by dividing its space by the change in its value. What it means is in a function is the derivative of that function. Example: A more permanent pattern for f(x) = x ^ 2 is f ʹ( x ) = 2 x. Therefore, 3 slope for this graph at point x = f(3) = f ʹ(3) = 2× 3 = 6.
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