Created on 2024-06-20Asked by Penelope Harris (Solvelet student)
Solve the separable differential equation dxdy=xy with the initial condition y(0)=1.
Solution
To solve the separable differential equation dxdy=xy with the initial condition y(0)=1: 1. **Separate the variables:** ydy=xdx. 2. **Integrate both sides:** ∫y1dy=∫xdx,ln∣y∣=2x2+C. 3. **Solve for y:** y=e2x2+C=eC⋅e2x2. Let eC=C1, then: y=C1e2x2. 4. **Apply the initial condition y(0)=1:** 1=C1e0⟹C1=1. 5. **Solution:** y=e2x2. Therefore, the solution to the differential equation is y=e2x2. Solved on Solvelet with Basic AI Model
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DefinitionA separable equation has the form g(y)dy=f(x)dx, So the variables are on opposite sides of the equation. The equation xdx = ydy is also an instance of a separable equation