Created on 2024-06-20Asked by Luna Martinez (Solvelet student)
Find all the cube roots of the complex number z=8+8i.
Solution
To find all the cube roots of the complex number z=8+8i: 1. **Express z in polar form:** z=8+8i=82(cos4π+isin4π). 2. **Apply De Moivre's Theorem for cube roots:** z1/3=(82)1/3(cos3π/4+2kπ+isin3π/4+2kπ),k=0,1,2. 3. **Calculate the cube roots:** (82)1/3=232. For k=0: cos+π/12isin.π/12 For k=1: cos+9π/12isin.9π/12 For k=2: cos+17π/12isin.17π/12 4. **Result:** The three cube roots are: 232(cos12π+isin12π),232(cos43π+isin43π),232(cos1217π+isin1217π).Solved on Solvelet with Basic AI Model
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DefinitionThe roots of a complex number are the solutions to equations of the form zn=w where z, w are complex numbers. The roots can be obtained using De Moivre's method as follows (z_k = Solution Roots of Complex numbers Finding using De moivre's Formula.