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Riemann Sums Calculator

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Example
Created on 2024-06-20Asked by Mila Taylor (Solvelet student)
Use a right Riemann sum with n=4n = 4 to approximate the integral 02(4x2)dx. \int_{0}^{2} (4 - x^2) \, dx.

Solution

To approximate 02(4x2)dx\int_{0}^{2} (4 - x^2) \, dx using a right Riemann sum with n=4n = 4: 1. **Divide the interval [0,2][0, 2] into n=4n = 4 subintervals of equal width:** Δx=204=0.5. \Delta x = \frac{2 - 0}{4} = 0.5. 2. **Determine the right endpoints of each subinterval:** x1=0.5,x2=1.0,x3=1.5,x4=2.0. x_1 = 0.5, \quad x_2 = 1.0, \quad x_3 = 1.5, \quad x_4 = 2.0. 3. **Evaluate the function at each right endpoint:** f(x1)=4(0.5)2=40.25=3.75, f(x_1) = 4 - (0.5)^2 = 4 - 0.25 = 3.75, f(x2)=4(1.0)2=41=3, f(x_2) = 4 - (1.0)^2 = 4 - 1 = 3, f(x3)=4(1.5)2=42.25=1.75, f(x_3) = 4 - (1.5)^2 = 4 - 2.25 = 1.75, f(x4)=4(2.0)2=44=0. f(x_4) = 4 - (2.0)^2 = 4 - 4 = 0. 4. **Calculate the right Riemann sum:** R4=Δx[f(x1)+f(x2)+f(x3)+f(x4)], R_4 = \Delta x [f(x_1) + f(x_2) + f(x_3) + f(x_4)], R4=0.5[3.75+3+1.75+0]=0.58.5=4.25. R_4 = 0.5 [3.75 + 3 + 1.75 + 0] = 0.5 \cdot 8.5 = 4.25. Therefore, the approximate value of the integral using a right Riemann sum with n=4n = 4 is 4.254.25. Solved on Solvelet with Basic AI Model
Some of the related questions asked by Harper Lewis on Solvelet
1. Estimate the area under the curve y=x2 y = x^2 on the interval [0,2] [0, 2] using four rectangles and right endpoints.2. Use a Riemann sum to approximate the area under the curve y=x y = \sqrt{x} on the interval [0,1][0, 1] using six subintervals of equal width.,
DefinitionIn calculus, Riemann sums are methods for approximating the total area under a curve on a graph, otherwise known as the integral of a function. They represent the sum of rectangles or trapezoids that estimate the area. Example: The left Riemann sum is an approximation of ∫ab​f(x)dx by adding the areas of f(xi​)Δx where i=0,1,...,n−1, and Δx=nb−a​.
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