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Relative degree of an algebraic expression Calculator

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Example
Created on 2024-06-20Asked by Camila Perez (Solvelet student)
Find the relative degree of the algebraic expression: 3x5+2x3+x2x4+5x2+1. \frac{3x^5 + 2x^3 + x}{2x^4 + 5x^2 + 1}.

Solution

To find the relative degree of the algebraic expression 3x5+2x3+x2x4+5x2+1\frac{3x^5 + 2x^3 + x}{2x^4 + 5x^2 + 1}: 1. **Identify the degrees of the numerator and the denominator:** - The degree of the numerator 3x5+2x3+x3x^5 + 2x^3 + x is 55. - The degree of the denominator 2x4+5x2+12x^4 + 5x^2 + 1 is 44. 2. **Calculate the relative degree:** Relative Degree=Degree of NumeratorDegree of Denominator=54=1. \text{Relative Degree} = \text{Degree of Numerator} - \text{Degree of Denominator} = 5 - 4 = 1. Therefore, the relative degree of the algebraic expression is 11. Solved on Solvelet with Basic AI Model
Some of the related questions asked by Logan Mitchell on Solvelet
1. Determine the relative degree of the polynomial f(x)=3x2+2x1 f(x) = 3x^2 + 2x - 1 .2. Classify the polynomial g(x)=5x42x3+3x27x+1 g(x) = 5x^4 - 2x^3 + 3x^2 - 7x + 1 by its degree and leading coefficient.,
DefinitionThe order of an algebraic expression is simply the difference in the respective powers of the numerator and denominator of an algebraic expression that contains two polynomials. Example: For x2+2x3+x2+1​ the relative degree is 3−2=1
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