Created on 2024-06-20Asked by Victoria Hill (Solvelet student)
Find the derivative of f(x)=sin(x)x2 using the quotient rule of differentiation.
Solution
To find the derivative of f(x)=sin(x)x2 using the quotient rule of differentiation: 1. Apply the quotient rule: (vu)′=v2u′v−uv′. 2. Identify u and v: u=x2,v=sin(x). 3. Compute the derivatives of u and v: u′=2x,v′=cos(x). 4. Apply the quotient rule: f′(x)=(sin(x))22x⋅sin(x)−x2⋅cos(x)=sin2(x)2xsin(x)−x2cos(x). Therefore, the derivative of f(x) is f′(x)=sin2(x)2xsin(x)−x2cos(x). Solved on Solvelet with Basic AI Model
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DefinitionA formula that used to evaluate the derivative of a function which is a division of two functions is called the quotient rule of differentiation. Which is read as (g(x)f(x) )'=g(x)2f'(x)g(x)−f(x)g'(x) . For instance, h(x)=xex which has a derivative equal to h′(x)=x2ex(x−1).