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Properties of logarithms Calculator

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Example
Created on 2024-06-20Asked by Scarlett Ramirez (Solvelet student)
Simplify the expression: loga(xy) \log_a(xy) .

Solution

To simplify the expression loga(xy) \log_a(xy) : 1. Use the property of logarithms: loga(xy)=loga(x)+loga(y). \log_a(xy) = \log_a(x) + \log_a(y). Therefore, loga(xy)=loga(x)+loga(y) \log_a(xy) = \log_a(x) + \log_a(y) . Solved on Solvelet with Basic AI Model
Some of the related questions asked by Luna Jackson on Solvelet
1. Simplify the expression log2(8)log2(2) \log_2(8) - \log_2(2) .2. Solve the equation log3(x)=2\log_3(x) = 2 for xx.
DefinitionLogarithms have important properties such as the product rule logb​(xy)=logb​(x)+logb​(y), the quotient rule logb​(yx​)=logb​(x)−logb​(y), and the power rule logb​(xy)=ylogb​(x) that provide us with tools for simplifying and manipulating complex logarithmic expressions. Examples: Employ the product rule, log(2⋅5)=log(2)+log(5)
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