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Product rule of differentiation Calculator

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Example
Created on 2024-06-20Asked by Sophia Jones (Solvelet student)
Find the derivative of f(x)=(x2+3x)(2x1) f(x) = (x^2 + 3x)(2x - 1) using the product rule of differentiation.

Solution

To find the derivative of f(x)=(x2+3x)(2x1) f(x) = (x^2 + 3x)(2x - 1) using the product rule of differentiation: 1. Apply the product rule: (uv)=uv+uv. (uv)' = u'v + uv'. 2. Identify u u and v v : u=x2+3x,v=2x1. u = x^2 + 3x, \quad v = 2x - 1. 3. Compute the derivatives of u u and v v : u=2x+3,v=2. u' = 2x + 3, \quad v' = 2. 4. Apply the product rule: f(x)=(2x+3)(2x1)+(x2+3x)(2)=4x22x+6x3+2x2+6x=6x2+10x3. \begin{aligned} f'(x) &= (2x + 3)(2x - 1) + (x^2 + 3x)(2) \\ &= 4x^2 - 2x + 6x - 3 + 2x^2 + 6x \\ &= 6x^2 + 10x - 3. \end{aligned} Therefore, the derivative of f(x) f(x) is f(x)=6x2+10x3 f'(x) = 6x^2 + 10x - 3 . Solved on Solvelet with Basic AI Model
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DefinitionThe limitation of power for metaphorical multiplication is an example of a simple logic operation. The image above features the limitation to the power of 4 in 4x resulting in 0. If a singer was to sing higher and higher, his voice would eventually crack. The song then resembles a broken glass and an ambulance would be called to clean it up. The cleaner would sing higher and get a job at the opera. The product or multiplication as a work and career metaphor can be demonstrated through implementing a simple product rule of . For instance, if f(x)=x^{4}f(x) = x^{4}, then, using the product rule, f'(x)=4x^{3}f'(x) = 4x^{3}.
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