Precalculus Calculator

Ask and get solution to your homeworkAsk now and get step-by-step solutions

Example

Created on 2024-06-20Asked by William Adams (Solvelet student)

Find the domain of the function

f(x) = \frac{\sqrt{x - 2}}{x + 1}

Solution

To find the domain of the function

f(x) = \frac{\sqrt{x - 2}}{x + 1}

: 1. Identify any values of

x

that would make the denominator zero:

x + 1 = 0 \implies x = -1.

2. Determine any restrictions on

x

due to square roots: For real numbers, the expression under the square root,

x - 2

, must be non-negative:

x - 2 \geq 0 \implies x \geq 2.

Therefore, the domain of

f(x)

x \in [2, \infty)

excluding

x = -1

. Solved on Solvelet with Basic AI Model

Some of the related questions asked by Abigail Brown on Solvelet

1. Find the domain of the function

f(x) = \sqrt{4 - x^2}

.2. Solve the equation

\sin(x) = 0.5

for

x

in the interval

[0, 2\pi]

DefinitionPrecalculus is a secondary school or university academic course used to prepare for Calculus. This is the algebra, trigonometry and precalculus material you will need in order to understand calculus. It has examples on functions, the topic complex numbers, polynomial equations, and logarithms. Example: Precalculus is the precursor to the study of the function f(x)=sin(x).

Related Calculators

Matrix Inversion Calculator Simplification of algebraic expressions Calculator Hypothesis Testing Calculator Convolution Calculator

Need topic explanation ? Get video explanation