Created on 2024-06-20Asked by Theodore Lopez (Solvelet student)
Solve the partial differential equation ∂t∂u=k∂x2∂2u subject to the initial condition u(x,0)=e−x2.
Solution
To solve the partial differential equation ∂t∂u=k∂x2∂2u subject to the initial condition u(x,0)=e−x2: 1. The general solution of the heat equation ∂t∂u=k∂x2∂2u is given by: u(x,t)=4πkt1∫−∞∞e−4kt(x−y)2u(y,0)dy. 2. For u(y,0)=e−y2: u(x,t)=4πkt1∫−∞∞e−4kt(x−y)2e−y2dy. 3. Simplify the integral: u(x,t)=4πkt1∫−∞∞e−(4kt(x−y)2+y2)dy. Therefore, the solution to the partial differential equation is given by the integral formula above. Solved on Solvelet with Basic AI Model
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DefinitionThe method of partial fraction is used to simplify rational functions by breaking it down in simpler fractions. This helps in integrating and solving differential equations easily. For instance: So (x+1)(x+2)2x+3 is x+1A+x+2B.