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Partial Differential Equations Calculator

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Example
Created on 2024-06-20Asked by Theodore Lopez (Solvelet student)
Solve the partial differential equation ut=k2ux2 \frac{\partial u}{\partial t} = k \frac{\partial^2 u}{\partial x^2} subject to the initial condition u(x,0)=ex2 u(x,0) = e^{-x^2} .

Solution

To solve the partial differential equation ut=k2ux2 \frac{\partial u}{\partial t} = k \frac{\partial^2 u}{\partial x^2} subject to the initial condition u(x,0)=ex2 u(x,0) = e^{-x^2} : 1. The general solution of the heat equation ut=k2ux2 \frac{\partial u}{\partial t} = k \frac{\partial^2 u}{\partial x^2} is given by: u(x,t)=14πkte(xy)24ktu(y,0)dy. u(x,t) = \frac{1}{\sqrt{4\pi k t}} \int_{-\infty}^{\infty} e^{-\frac{(x-y)^2}{4k t}} u(y,0) \, dy. 2. For u(y,0)=ey2 u(y,0) = e^{-y^2} : u(x,t)=14πkte(xy)24ktey2dy. u(x,t) = \frac{1}{\sqrt{4\pi k t}} \int_{-\infty}^{\infty} e^{-\frac{(x-y)^2}{4k t}} e^{-y^2} \, dy. 3. Simplify the integral: u(x,t)=14πkte((xy)24kt+y2)dy. u(x,t) = \frac{1}{\sqrt{4\pi k t}} \int_{-\infty}^{\infty} e^{-\left( \frac{(x-y)^2}{4k t} + y^2 \right)} \, dy. Therefore, the solution to the partial differential equation is given by the integral formula above. Solved on Solvelet with Basic AI Model
Some of the related questions asked by Mateo Anderson on Solvelet
1. Solve the wave equation 2ut2=c22ux2 \frac{\partial^2 u}{\partial t^2} = c^2 \frac{\partial^2 u}{\partial x^2} subject to given initial and boundary conditions.2. Analyze the existence and uniqueness of solutions to the heat equation ut=uxxu_t = u_{xx} with given initial and boundary conditions.
DefinitionThe method of partial fraction is used to simplify rational functions by breaking it down in simpler fractions. This helps in integrating and solving differential equations easily. For instance: So (x+1)(x+2)2x+3​ is x+1A​+x+2B​.
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