Created on 2024-06-20Asked by Liam Mitchell (Solvelet student)
Verify if the given set and distance function form a metric space. Consider the set R with the distance function d(x,y)=∣x−y∣.
Solution
To verify if (R,d) where d(x,y)=∣x−y∣ forms a metric space, we need to check the following properties: 1. **Non-negativity**: d(x,y)≥0for allx,y∈R. Since ∣x−y∣ is always non-negative, this property holds. 2. **Identity of Indiscernibles**: d(x,y)=0if and only ifx=y. If x=y, then ∣x−y∣=0. Conversely, if ∣x−y∣=0, then x=y. 3. **Symmetry**: d(x,y)=d(y,x)for allx,y∈R. Since ∣x−y∣=∣y−x∣, this property holds. 4. **Triangle Inequality**: d(x,z)≤d(x,y)+d(y,z)for allx,y,z∈R. We need to show that ∣x−z∣≤∣x−y∣+∣y−z∣. This follows from the properties of absolute values. Therefore, the set R with the distance function d(x,y)=∣x−y∣ forms a metric space. Solved on Solvelet with Basic AI Model
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DefinitionA metric space is defined in a set containing a metric (i.e., distance function) which defines the distance between two element. These properties include non-negativity, symmetry, triangle inequality and identity of indiscernibles. Ex) Real numbers R with the usual distance ( d(x, y) = | x-y.