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Metric Spaces Calculator

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Example
Created on 2024-06-20Asked by Liam Mitchell (Solvelet student)
Verify if the given set and distance function form a metric space. Consider the set R \mathbb{R} with the distance function d(x,y)=xy d(x, y) = |x - y| .

Solution

To verify if (R,d) (\mathbb{R}, d) where d(x,y)=xy d(x, y) = |x - y| forms a metric space, we need to check the following properties: 1. **Non-negativity**: d(x,y)0for allx,yR. d(x, y) \geq 0 \quad \text{for all} \quad x, y \in \mathbb{R}. Since xy |x - y| is always non-negative, this property holds. 2. **Identity of Indiscernibles**: d(x,y)=0if and only ifx=y. d(x, y) = 0 \quad \text{if and only if} \quad x = y. If x=y x = y , then xy=0 |x - y| = 0 . Conversely, if xy=0 |x - y| = 0 , then x=y x = y . 3. **Symmetry**: d(x,y)=d(y,x)for allx,yR. d(x, y) = d(y, x) \quad \text{for all} \quad x, y \in \mathbb{R}. Since xy=yx |x - y| = |y - x| , this property holds. 4. **Triangle Inequality**: d(x,z)d(x,y)+d(y,z)for allx,y,zR. d(x, z) \leq d(x, y) + d(y, z) \quad \text{for all} \quad x, y, z \in \mathbb{R}. We need to show that xzxy+yz |x - z| \leq |x - y| + |y - z| . This follows from the properties of absolute values. Therefore, the set R \mathbb{R} with the distance function d(x,y)=xy d(x, y) = |x - y| forms a metric space. Solved on Solvelet with Basic AI Model
Some of the related questions asked by Elijah Allen on Solvelet
1. Determine whether the set of real numbers R \mathbb{R} with the absolute value metric is complete.2. Find the open ball B(x0,r)B(x_0, r) in the metric space R2\mathbb{R}^2 with the Euclidean distance metric, where x0=(1,2)x_0 = (1, 2) and r=3r = 3.
DefinitionA metric space is defined in a set containing a metric (i.e., distance function) which defines the distance between two element. These properties include non-negativity, symmetry, triangle inequality and identity of indiscernibles. Ex) Real numbers R with the usual distance ( d(x, y) = | x-y.
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