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Linear Approximation Calculator

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Example
Created on 2024-06-20Asked by Owen Moore (Solvelet student)
Use linear approximation to estimate the value of 4.1 \sqrt{4.1} .

Solution

To use linear approximation to estimate 4.1 \sqrt{4.1} , we start with the function f(x)=x f(x) = \sqrt{x} . The linear approximation of f(x) f(x) near x=a x = a is given by: L(x)=f(a)+f(a)(xa) L(x) = f(a) + f'(a)(x - a) Here, let a=4 a = 4 . Then: f(x)=xandf(x)=12x f(x) = \sqrt{x} \quad \text{and} \quad f'(x) = \frac{1}{2\sqrt{x}} So: f(4)=4=2andf(4)=124=14 f(4) = \sqrt{4} = 2 \quad \text{and} \quad f'(4) = \frac{1}{2\sqrt{4}} = \frac{1}{4} The linear approximation near x=4 x = 4 is: L(x)=2+14(x4) L(x) = 2 + \frac{1}{4}(x - 4) Now, substitute x=4.1 x = 4.1 : L(4.1)=2+14(4.14)=2+14(0.1)=2+0.025=2.025 L(4.1) = 2 + \frac{1}{4}(4.1 - 4) = 2 + \frac{1}{4}(0.1) = 2 + 0.025 = 2.025 Therefore, the linear approximation of 4.1 \sqrt{4.1} is: 2.025 2.025 Solved on Solvelet with Basic AI Model
Some of the related questions asked by Sophia White on Solvelet
1. Use linear approximation to estimate 3.1 \sqrt{3.1} .2. Approximate e0.02 e^{0.02} using linear approximation
DefinitionA linear approximation approximates the value of a function at a given point by the tangent line to the function at a close point. A differentiable function f(x) at x=a, so the linear approximation: f(x)≅f(a)+f′(a)(x−a). This is a method of numerical mathematical methods and the determinate errors. For example, trying to find 4.1 (to the nearest tenth) with x = f(x) as a linear approximation and x = 4 can be found as x = 2 + 4/1 (0.1) = 2.01.
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