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Example
Created on 2024-06-20Asked by Chloe Taylor (Solvelet student)
Evaluate the integral (3x2+2x+1)dx \int (3x^2 + 2x + 1) \, dx .

Solution

To evaluate the integral (3x2+2x+1)dx \int (3x^2 + 2x + 1) \, dx : Integrate each term separately: 3x2dx+2xdx+1dx \int 3x^2 \, dx + \int 2x \, dx + \int 1 \, dx Use the power rule for integration: xndx=xn+1n+1+C \int x^n \, dx = \frac{x^{n+1}}{n+1} + C Apply the power rule to each term: 3x2dx=3x33=x3 \int 3x^2 \, dx = 3 \cdot \frac{x^3}{3} = x^3 2xdx=2x22=x2 \int 2x \, dx = 2 \cdot \frac{x^2}{2} = x^2 1dx=x \int 1 \, dx = x Combine the results: (3x2+2x+1)dx=x3+x2+x+C \int (3x^2 + 2x + 1) \, dx = x^3 + x^2 + x + C Therefore, the integral (3x2+2x+1)dx \int (3x^2 + 2x + 1) \, dx is: (3x2+2x+1)dx=x3+x2+x+C \int (3x^2 + 2x + 1) \, dx = x^3 + x^2 + x + C Where C C is the constant of integration. Solved on Solvelet with Basic AI Model
Some of the related questions asked by Chloe Thomas on Solvelet
1. Evaluate the integral 01(3x2+2x+1)dx\int_0^1 (3x^2 + 2x + 1) \, dx,2. Evaluate the integral x2+3x2(x1)(x+2)dx\int \frac{x^2 + 3x - 2}{(x - 1)(x + 2)} \, dx using partial fraction decomposition.,
DefinitionIntegration is a mathematical technique that simply collects the quantities, for example areas under curve, total distance covered, accumulated quantities in an interval. The two chief types are the definite integral, which represents a number, and the indefinite integral, which represents a function (the antiderivative of the given function). Calculus is the study of integrals and is essential for solving physics, engineering, economics ans many other problems. Where The definite integral ∫ab​f(x)dx denotes the area between curve f(x) from x=a to x=b.
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