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Homeomorphisms Calculator

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Example
Created on 2024-06-20Asked by Chloe Scott (Solvelet student)
Prove that the interval (0,1) (0, 1) is homeomorphic to R \mathbb{R} .

Solution

To prove that the interval (0,1) (0, 1) is homeomorphic to R \mathbb{R} : We need to find a continuous bijective function with a continuous inverse between (0,1) (0, 1) and R \mathbb{R} . Consider the function f:(0,1)R f: (0, 1) \to \mathbb{R} defined by: f(x)=tan(πxπ2) f(x) = \tan\left( \pi x - \frac{\pi}{2} \right) This function is continuous and bijective. The inverse function f1:R(0,1) f^{-1}: \mathbb{R} \to (0, 1) is given by: f1(y)=1π(arctan(y)+π2) f^{-1}(y) = \frac{1}{\pi} \left( \arctan(y) + \frac{\pi}{2} \right) The inverse function f1(y) f^{-1}(y) is also continuous. Since f(x) f(x) is a continuous bijection with a continuous inverse, it is a homeomorphism. Therefore, the interval (0,1) (0, 1) is homeomorphic to R \mathbb{R} . Solved on Solvelet with Basic AI Model
Some of the related questions asked by Chloe Adams on Solvelet
1. Determine whether the function f(x)=x3f(x) = x^3 is a homeomorphism between the real line R\mathbb{R} and the interval [0,)[0, \infty),2. Solve the system of equations {x+y=3,2xy=1}\{x + y = 3, 2x - y = 1\} using the method of elimination and determine whether the system is homogeneous or heterogeneous.,
DefinitionIn other words, homeomorphisms are bicontinuous functions between topological spaces. Its preserves the topology of spaces, like for example, connectedness, compactness. A second type of structure, the classification of spaces according to their shape, that is, according to the homeomorphisms, by which we learn itself is called the topology. If they are homeomorphic to each other -we say it more informally that these are topologically equivalent two spaces. For an example, the function f(x) = x3 is a homeomorphism of the real line R onto itself: it is continuous and bijective, and its inverse is also continuous.
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