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Example
Created on 2024-06-20Asked by Madison Martinez (Solvelet student)
Determine the orbit and the stabilizer of the element 1 under the action of the group Z3 \mathbb{Z}_3 on the set {0,1,2} \{0, 1, 2\} by addition modulo 3.

Solution

To determine the orbit and the stabilizer of the element 1 under the action of the group Z3 \mathbb{Z}_3 on the set {0,1,2} \{0, 1, 2\} by addition modulo 3: The action is given by: gx=(g+x)mod3 g \cdot x = (g + x) \mod 3 For gZ3={0,1,2} g \in \mathbb{Z}_3 = \{0, 1, 2\} and x=1 x = 1 : - 01=(0+1)mod3=1 0 \cdot 1 = (0 + 1) \mod 3 = 1 - 11=(1+1)mod3=2 1 \cdot 1 = (1 + 1) \mod 3 = 2 - 21=(2+1)mod3=0 2 \cdot 1 = (2 + 1) \mod 3 = 0 The orbit of 1 is: Orbit(1)={0,1,2} \text{Orbit}(1) = \{0, 1, 2\} The stabilizer of 1 is the set of elements gZ3 g \in \mathbb{Z}_3 such that g1=1 g \cdot 1 = 1 : g1=(g+1)mod3=1 g \cdot 1 = (g + 1) \mod 3 = 1 g+11mod3 g + 1 \equiv 1 \mod 3 g0mod3 g \equiv 0 \mod 3 The stabilizer of 1 is: Stab(1)={0} \text{Stab}(1) = \{0\} Solved on Solvelet with Basic AI Model
Some of the related questions asked by Eleanor Lopez on Solvelet
1. Determine the orbit and stabilizer of the element 22 under the action of the group G={1,2,3,4,5}G = \{1, 2, 3, 4, 5\} with the operation defined by addition modulo 55,2. Find the number of distinct orbits of the group G={1,1,i,i}G = \{1, -1, i, -i\} acting on the set S={1,1,i,i}S = \{1, -1, i, -i\} by multiplication.,
DefinitionAdditionally, if we consider what is known as a group action, with G denoting a group and X a set, we have a description of the behaviour of the group G on a set X by assigning to each element of G a transformation of X. Formally speaking a group action is a function ⋅:G×X→X that sates a bunch of properties, like identity and compatibility. Group actions arise in algebra, geometry, and combinatorics to investigate symmetries, permutations, and properties of sets that are invariant under transformations by groups. Basis, Key to Understanding Algebraic Objects! Example : If G is a group, X is a set, a group action ⋅ satisfies e⋅x=x (where e is the identity element of G ) and (gh)⋅x=g⋅(h⋅x), for all g,h∈G, x∈X.
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