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Fourier Transform of Periodic Functions Calculator

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Example
Created on 2024-06-20Asked by Sebastian Nelson (Solvelet student)
Find the Fourier transform of the periodic function f(x)=sin(x) f(x) = \sin(x) with period 2π 2\pi .

Solution

The Fourier transform of the periodic function f(x)=sin(x) f(x) = \sin(x) with period 2π 2\pi does not exist in the conventional sense, as the function is not absolutely integrable. However, it can be represented using Dirac delta functions: F[f(x)]=2πn=δ(ωn). \mathcal{F}[f(x)] = 2\pi \sum_{n=-\infty}^{\infty} \delta(\omega - n). Solved on Solvelet with Basic AI Model
Some of the related questions asked by Mila Nelson on Solvelet
1. Compute the Fourier transform of the square wave function f(t)=1 f(t) = 1 for π<t<0 -\pi < t < 0 and f(t)=1 f(t) = -1 for 0<t<π 0 < t < \pi .2. Find the frequency components of the periodic function g(t)=sin(t)+cos(3t) g(t) = \sin(t) + \cos(3t) by computing its Fourier transform.
DefinitionIn mathematics, the Fourier transform of a periodic function is a generalization of the Fourier series to non-periodic functions and is used to represent a function as a sum of fundamental frequencies. This property implies harmonics in the frequency domain, meaning that the Fourier transform of a periodic function is nonzero only at integer multiples of the fundamental frequency. In such varied areas as signal processing, communication systems or mathematical physics (to name just a few) the analysis of such functions is crucial to the understanding of periodic signals, to the synthesis of waveforms, or to the solution of differential equations with periodic boundary conditions. For example, the Fourier transform of the periodically defined function f(x) with period T is defined as F(ω)=∑n=−∞∞​cn​δ(ω−T2πn​), where cn​ are the Fourier coefficients of the function.
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