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First Order Differential Equations Calculator

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Example
Created on 2024-06-20Asked by Liam Sanchez (Solvelet student)
Solve the first-order differential equation dydx=2x \frac{dy}{dx} = 2x with initial condition y(0)=1 y(0) = 1 .

Solution

To solve the first-order differential equation dydx=2x \frac{dy}{dx} = 2x with initial condition y(0)=1 y(0) = 1 : dydx=2x \frac{dy}{dx} = 2x dy=2xdx dy = 2x \, dx dy=2xdx \int dy = \int 2x \, dx y=x2+C y = x^2 + C Given y(0)=1 y(0) = 1 , we find C C : 1=02+C 1 = 0^2 + C C=1 C = 1 So the solution is y=x2+1 y = x^2 + 1 . Solved on Solvelet with Basic AI Model
Some of the related questions asked by Lucas Mitchell on Solvelet
1. Solve the first-order differential equation dydx=2x3 \frac{dy}{dx} = 2x - 3 .2. Determine whether the function y=ex y = e^{-x} is a solution to the first-order differential equation dydx+y=0 \frac{dy}{dx} + y = 0 .
DefinitionOrdinary Differential Equations in which the order of the derivative of y is no more than 1 (i.e. the highest derivative is the first derivative ) Depending on the properties and coefficients involved, first-order ODEs can be of the separable, linear, exact, or homogeneous type, as well as Bernoulli equations. We can use first-order ODEs to model rates of change, growth, decay phenomena; like in physics, engineering, and mathematical modeling. Analytically it is solved with the help of techniques involving separation of variables, integrating factors, and variation of parameters, and numerically it is solved using Eulers method and Runge-Kutta methods. For example, the first-order ODE dxdy​=x2+y is non-linear only with respect to the solution z(x,y) to produce exponential growth or decay with a quadratic source term, and can be solved using integrating factors to convert this DE into a linear relation or the solution can be approximate using numerical methods.
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