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Differentiation Calculator

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Example
Created on 2024-06-20Asked by Layla Nelson (Solvelet student)
Find the derivative of the function f(x)=x3+2x23x+1 f(x) = x^3 + 2x^2 - 3x + 1 .

Solution

Step 1: Identify the function f(x)=x3+2x23x+1 f(x) = x^3 + 2x^2 - 3x + 1 . Step 2: Use the power rule for differentiation: ddx(axn)=naxn1. \frac{d}{dx} (ax^n) = nax^{n-1}. Step 3: Apply the power rule to each term: f(x)=3x2+4x3. f'(x) = 3x^2 + 4x - 3. Step 4: Conclusion. The derivative of f(x)=x3+2x23x+1 f(x) = x^3 + 2x^2 - 3x + 1 is f(x)=3x2+4x3 f'(x) = 3x^2 + 4x - 3 . Solved on Solvelet with Basic AI Model
Some of the related questions asked by Jackson Moore on Solvelet
1. Find the derivative of the function f(x)=3x22x+1 f(x) = 3x^2 - 2x + 1 .2. Determine the slope of the tangent line to the curve y=4x2 y = \sqrt{4 - x^2} at the point (1,3) (1, \sqrt{3}) .
DefinitionDifferentiation is a basic concept in calculus, which allows us to find the rate of change, i.e., the slope of the function at a certain point. Differentiation is a fundamental tool in calculus which can be used to analyze and model functions, determine relative and absolute extrema of functions, solve differential equations, and much more. The derivative of a function f(x) with respect to its independent variable x can be written as f′(x) = dfdx(x). For ex:, the derivatire of the function f(x)=x2 with respect to x is f′(x)=2x, the slope of the tangent to the curve y=x2 at any point x.Learn & solve Differentiation related problems with SolveletAI advanced step-by-step solutions.
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