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Continuity and Compactness Calculator

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Example
Created on 2024-06-20Asked by Sebastian Nelson (Solvelet student)
Determine if the function f(x)=1x f(x) = \frac{1}{x} is continuous on the interval (0,1] (0, 1] .

Solution

Step 1: Identify the function f(x)=1x f(x) = \frac{1}{x} and the interval (0,1] (0, 1] . Step 2: Check the continuity of f(x) f(x) on (0,1] (0, 1] . Step 3: f(x) f(x) is continuous on (0,1] (0, 1] because it is defined and differentiable on the interval. Step 4: Conclusion. The function f(x)=1x f(x) = \frac{1}{x} is continuous on the interval (0,1] (0, 1] . Solved on Solvelet with Basic AI Model
Some of the related questions asked by Scarlett Davis on Solvelet
1. Determine whether the function f(x)=1x f(x) = \frac{1}{x} is continuous on the interval (0,) (0, \infty) 2. Show that the closed interval [0,1] [0, 1] is compact.,
DefinitionContinuity and compactness are interesting properties of topological spaces that have to do with how functions can be defined within the spaces and with the behaviour of sets in these spaces. Continuity preserves continuity and points closed to each other under a map, but compactness implies a set is closed and bounded loving finite open covers. These ideas are foundational of topology, analysis, and geometry to the approach continuity, and convergence of sequences and functions. I.e., the function f(x)=x1​ is continuous on the interval (0,∞), but not so on a compact domain [0,∞) even though it is bound.
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